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0.0909 Repeating As A Fraction

https://www.cuemath.com/ncert-solutions/write-the-following-in-decimal-class-and-say-what-kind-of-decimal-expansion-each-has-i-36-100-2-1-eleven-iii-iv-ane-8-iv-3-13-5-ii-xi-vi-329-400/

Write the following in decimal form and say what kind of decimal expansion each has: i) 36/100  2) 1/xi  3)\(four{\Large\frac{ane}{8}}\) 4) 3/13  5) 2/11  six) 329/400

Solution:

i) 36/100

36/100 = 0.36

Thus, 36/100 in decimal format is represented every bit 0.36.

This is a terminating decimal number.

2) 1/11

The residue 1 keeps repeating. And then, 1/11 = 0.0909… and it can be written as 1/11 =
0.09

This is a non-terminating recurring decimal.

iii)
\(iv{\Large\frac{i}{8}}\)

\(iv{\Large\frac{1}{viii}}\) tin can be expressed as 33/8 in terms of improper fraction.

Write the following in decimal form and say what kind of decimal expansion each has: i) 36/100  ii) 1/11  iii)4 1/8 iv) 3/13  v) 2/11  vi) 329/400

Thus,
\(iv{\Big\frac{one}{8}}\)
= 33/eight = 4.125

Thus,
\(4{\Big\frac{1}{8}}\)
in decimal grade is written as 4.125.

This is a terminating decimal number because the residual is nix.

four) three/13


Write the following in decimal form and say what kind of decimal expansion each has: i) 36/100  ii) 1/11  iii)4 1/8 iv) 3/13  v) 2/11  vi) 329/400

Thus, 3/xiii = 0.23076923…

We see that the prepare of numbers 230769 after the decimal point keeps repeating. So, this is a non-terminating recurring decimal.

v) 2/11

Write the following in decimal form and say what kind of decimal expansion each has: i) 36/100  ii) 1/11  iii)4 1/8 iv) 3/13  v) 2/11  vi) 329/400

Thus, 2/11 = 0.1818

Here, we meet that the block of numbers 18 keeps repeating. Hence, this is a non-terminating recurring decimal.

vi) 329/400

329/400 = 329 ÷ (iv × 100) = 0.8225

Write the following in decimal form and say what kind of decimal expansion each has: i) 36/100  ii) 1/11  iii)4 1/8 iv) 3/13  v) 2/11  vi) 329/400

Now, 82.25/100 = 0.8225

Thus, 329/400 in decimal form is written as 0.8225.

This is a terminating decimal number because the residuum is nix.

☛ Bank check:
NCERT Solutions for Course 9 Maths Chapter 1


Video Solution:

Write the following in decimal form and say what kind of decimal expansion each has: i) 36/100  ii) 1/11  iii)
\(iv{\Large\frac{one}{viii}}\)  iv) 3/13  five) 2/11  vi) 329/400

NCERT Solutions Course 9 Maths Chapter 1 Do 1.iii Question one

Summary:

We see that in decimal course 36/100,
\(4{\Large\frac{1}{eight}}\), 329/400 are terminating decimals, whereas 1/eleven, iii/xiii, 2/11 are not-terminating recurring decimal.


☛ Related Questions:

  • You know that 1/seven = 0.142587. Tin can you predict what the decimal expansions of two/7, 3/seven, four/seven, 5/7, six/7 are, without actually doing the long segmentation? If so, how?
  • Express the following in the class of p/q, where p and q are integers and q ≠ 0. i) 0.half dozen ii) 0.47 3) 0.001
  • Express 0.99999 …. in the form of p/q. Are yous surprised with your respond? With your teacher and classmates discuss why the answer makes sense?
  • What tin be the maximum number of digits be in the repeating block of digits in the decimal expansion of 1/17? Perform the division to check your answer.

Source: https://www.cuemath.com/ncert-solutions/write-the-following-in-decimal-form-and-say-what-kind-of-decimal-expansion-each-has-i-36-100-ii-ane-11-iii-four-one-8-4-3-xiii-v-two-11-half dozen-329-400/

0.0909 Repeating As A Fraction,

Source: https://en.asriportal.com/108435/write-numbers-in-decimal-and-write-decimal-expansion-type-i-36-100-ii-1-11-iii-4-1-8-iv-3-13-v-2-11-vi-329-400/

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